4x^2+1.5x-3.75=0

Solution for 4x^2+1.5x-3.75=0 equation:

4x^2+1.5x-3.75=0

a = 4; b = 1.5; c = -3.75;
Δ = b2-4ac
Δ = 1.52-4·4·(-3.75)
Δ = 62.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.5)-\sqrt{62.25}}{2*4}=\frac{-1.5-\sqrt{62.25}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.5)+\sqrt{62.25}}{2*4}=\frac{-1.5+\sqrt{62.25}}{8}
$